Rigid body Newton’s law homework

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SUMMARY

The discussion focuses on the application of Newton's laws in rigid body dynamics, specifically regarding a rod in centripetal motion. Participants clarify that the rod does not rotate around point G due to the constraints of the ropes, resulting in zero angular acceleration. The radius of 0.4 meters is confirmed as the distance from the center of motion to the ends of the rod. The conversation emphasizes the importance of understanding the conditions under which angular acceleration can be considered zero in rigid body problems.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with rigid body dynamics
  • Knowledge of centripetal motion principles
  • Basic concepts of angular acceleration and moment of inertia
NEXT STEPS
  • Study the principles of rigid body dynamics in detail
  • Learn about centripetal motion and its applications in physics
  • Explore the concept of angular acceleration in various contexts
  • Review problem-solving techniques for rigid body motion using free body diagrams
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Students studying physics, particularly those focusing on mechanics, as well as educators looking to enhance their understanding of rigid body dynamics and Newton's laws.

Pipsqueakalchemist
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Homework Statement
Problem and solution below
Relevant Equations
F = ma
Moment equation
For this problem I know how to get the answers but I have a few things I’m not 100% sure about. First how do we know that the rod is experiencing centripetal motion? Second, when using moment about point G how do we know that the angular acceleration is equal to zero? And third the radius is 0.4 because the two ends of the rod are in motion with radius of 0.4 right?
 

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1. Because 200 N + 300 N > mg
2. Because the ropes fix the angle of the rod ##\rightarrow## it can't rotate around G
3. Yes
Pipsqueakalchemist said:
I know how to get the answers
yea, because it seems you have a solutions manual at your disposition ? PF rules in fact require you to post your own attempt at solution :smile:
 
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Well my test is on Monday and I still have another 10 question in the problem set. I can’t afford to get stuck on every single question.
 
I see. Was my reply in #2 ok with you ?

##\ ##
 
Yea I guess I see it. Since the bar isn’t rotating around point G or around any point on the bar itself so regardless of which point I chose the angular acceleration will always be zero right?
 
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002-four-bar-linkages-4-728.jpg

TintedHelpfulAdeliepenguin-size_restricted.gif
 
Hey you commented on my other post. The one with the tipping cabinet. Do you mind looking at it because I still have some confusion.
 
Pipsqueakalchemist said:
Hey you commented on my other post. The one with the tipping cabinet. Do you mind looking at it because I still have some confusion.
Me too. :frown:
 
Lol, yea Ik the signs don’t make sense
 

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