Analyzing Dynamics in Constant Acceleration w/Rindler & Equivalence

Click For Summary
SUMMARY

This discussion clarifies the use of Rindler coordinates in analyzing dynamics within a constantly accelerating reference frame. Rindler coordinates serve as the natural coordinates for an observer at rest in a rocket experiencing constant proper acceleration, allowing for the observation of objects in free fall as if under a pseudo-gravitational field. The principle of equivalence can simplify analysis by treating acceleration as a gravitational field, making it unnecessary to rely solely on Rindler coordinates. Ultimately, the choice between using Rindler coordinates or the principle of equivalence depends on which method simplifies the problem-solving process.

PREREQUISITES
  • Understanding of Rindler coordinates and their application in general relativity.
  • Familiarity with the principle of equivalence in physics.
  • Basic knowledge of inertial and non-inertial reference frames.
  • Concepts of gravitational fields and pseudo-forces in accelerating frames.
NEXT STEPS
  • Study the mathematical formulation of Rindler coordinates in general relativity.
  • Explore the principle of equivalence and its implications in different reference frames.
  • Learn about inertial forces, including Coriolis and centrifugal forces, in non-inertial frames.
  • Investigate the relationship between Rindler coordinates and rotating coordinate systems in classical mechanics.
USEFUL FOR

Physicists, students of general relativity, and anyone interested in the dynamics of accelerating reference frames and gravitational effects in physics.

e2m2a
Messages
354
Reaction score
13
TL;DR
When to use RIndler coordinates or the principle of equivalence
Not sure when to use Rindler coordinates to analyze dynamics in a constant accelerating reference system. Rindler coordinates seem messy because they are always changing. Wouldn't it be easier to invoke the principle of equivalence and treat the environment of an accelerating system as a gravitational field? For example, suppose an observer in an accelerating frame with constant acceleration throws a ball at a 45 deg angle with respect to his system. According to this observer he will see the path of the ball as a parabola. With respect to an inertial observer wouldn't it be unnecessary complex to try and figure out the path the accelerating observer sees my using RIndler coordinates to determine this?
 
Physics news on Phys.org
e2m2a said:
With respect to an inertial observer wouldn't it be unnecessary complex to try and figure out the path the accelerating observer sees my using RIndler coordinates to determine this?
Why would an inertial observer want to use Rindler coordinates?
 
  • Like
Likes   Reactions: vanhees71
Ibix said:
Why would an inertial observer want to use Rindler coordinates?
To determine what the observer in the accelerated frame observes for the motion of the ball or am I really confused about this?
 
e2m2a said:
Rindler coordinates seem messy because they are always changing.
No, they aren't. Look at the metric in Rindler coordinates. None of the metric coefficients are a function of Rindler coordinate time.
 
  • Like
Likes   Reactions: vanhees71
e2m2a said:
Wouldn't it be easier to invoke the principle of equivalence and treat the environment of an accelerating system as a gravitational field?
Um, that's what you are doing when you use Rindler coordinates. Rindler coordinates are the natural coordinates for an observer at rest in a rocket with constant proper acceleration, and an object inside the rocket that is dropped in free fall will appear to accelerate downward due to the (pseudo-)gravitational field inside the rocket.
 
  • Like
Likes   Reactions: vanhees71
Moderator's note: Thread level changed to "I".
 
e2m2a said:
To determine what the observer in the accelerated frame observes for the motion of the ball or am I really confused about this?
OK - but all the Rindler coordinates are is the "at rest" coordinates of the accelerated observer. You don't really need to use them except to express the final result if you want.

There's a close analogy with rotating coordinates in ordinary Euclidean geometry. It's often easier to work in Cartesian coordinates and solve a problem, write an object's path in terms of ##x,y,z## coordinates and then translate to polars and then rotating coordinates. There's nothing stopping you working entirely in the rotating coordinates, including all the inertial forces (Coriolis, etc) in your calculations, but you aren't obliged to do so.

Similarly, you can take your results in your inertial frame and transform them into the accelerated frame, or work in the accelerated frame where there's an inertial force (uniform gravitational field). Do whichever is easier.

Does that help?
 
  • Like
Likes   Reactions: vanhees71
Ibix said:
OK - but all the Rindler coordinates are is the "at rest" coordinates of the accelerated observer. You don't really need to use them except to express the final result if you want.

There's a close analogy with rotating coordinates in ordinary Euclidean geometry. It's often easier to work in Cartesian coordinates and solve a problem, write an object's path in terms of ##x,y,z## coordinates and then translate to polars and then rotating coordinates. There's nothing stopping you working entirely in the rotating coordinates, including all the inertial forces (Coriolis, etc) in your calculations, but you aren't obliged to do so.

Similarly, you can take your results in your inertial frame and transform them into the accelerated frame, or work in the accelerated frame where there's an inertial force (uniform gravitational field). Do whichever is easier.

Does that help?
Yes. Making things as simple as possible is always the most efficient method. Thank you.
 
  • Like
Likes   Reactions: vanhees71
e2m2a said:
Summary:: When to use RIndler coordinates or the principle of equivalence

Rindler coordinates seem messy because they are always changing.
Maybe you are doing something wrong. Rindler coordinates are both stationary and static. And Rindler observers form a timelike Killing vector field (which I guess is implied by the previous sentence). Can you explain what you mean here?
 
  • Like
Likes   Reactions: vanhees71

Similar threads

  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 29 ·
Replies
29
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 44 ·
2
Replies
44
Views
6K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 48 ·
2
Replies
48
Views
5K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 10 ·
Replies
10
Views
9K
  • · Replies 13 ·
Replies
13
Views
2K