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Hello,

Onhttp://math.ucr.edu/home/baez/physics/Relativity/SR/rocket.html [Broken] website it says in the section "below the rocket, something strange is happening" that the distance of an object which passes the accelerating observer never increases -c

I've done an exemplary calculation by computing the distance between horizon and accelerating observer and then compared it to c

Thanks in advance for your help!

Onhttp://math.ucr.edu/home/baez/physics/Relativity/SR/rocket.html [Broken] website it says in the section "below the rocket, something strange is happening" that the distance of an object which passes the accelerating observer never increases -c

^{2}/α. I think this means, that the Rindler Horizon is always located at that distance in the momentarily comoving frame. So I would expect that from my perspective on Earth the distance between the horizon and the accelerating observer is lorentzcontracted (although the horizon doesn't exist in my inertial frame, I should be able to calculate the distance at which a light signal will never reach the observer at a given point in time).I've done an exemplary calculation by computing the distance between horizon and accelerating observer and then compared it to c

^{2}/(αγ). Unfortunately I didn't get the same result. So before I write down my calculation, does it make sense at all to assume the distance is contracted in my frame or am I missing something?Thanks in advance for your help!

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