RL circuit differential equation for 48cos(60t) voltage source

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Vossi
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Homework Statement
See attached image
Relevant Equations
First Order Differential equation for electrical circuit
I'm confused at the part how 4Vc and 48 cos(60t) are deduced, that's all.
 
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  • Handwritten-style typeset ODE for an RC circuit: dVc/dt + 4Vc = 48 cos(60t), shown as the Question 1 solution of a challenge problem on an RC circuit with variable voltage source.
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Welcome to PhysicsForums. :smile:
Vossi said:
Homework Statement:: See attached image
Relevant Equations:: First Order Differential equation for electrical circuit

I'm confused at the part how 4Vc and 48 cos(60t) are deduced, that's all.

It looks like they are just giving the equation for one case of the values of R, C and the driving voltage source...

Printed worksheet page titled Challenge problem: RC circuit with variable voltage source, showing the RC circuit ODE dV_C/dt + V_C/(RC) = V_IN/RC, three numbered questions, and the start of a solution: dV_C/dt + 4V_C = 48 cos(60t).
 
Vossi said:
I'm confused at the part how 4Vc and 48 cos(60t) are deduced, that's all.
I don't get it, either.
The units for R and C should be in ohms and farads, so ##RC = (2 \times 10^3)(5 \times 10^{-6}) = 10 \times 10^{-3} = 10^{-2}## ohms-farads.
It's possible there is a mistake in the published answer.
 
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Yes, clearly RC=0.25 sec for the answer given. Like 50Kohm & 5uF, for example.