RLC circuit step response time domain

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Discussion Overview

The discussion revolves around finding the step response of a series RLC circuit in the time domain, specifically using Laplace Transforms and differential equations. Participants explore methods to derive the response and share their approaches.

Discussion Character

  • Exploratory, Technical explanation, Homework-related

Main Points Raised

  • One participant successfully found the step response of an RC circuit using Laplace Transforms but struggles with the RLC transfer function.
  • Another participant suggests reverting to differential equation notation to find the homogeneous and particular solutions, referring to them as transient and steady state solutions.
  • A different participant mentions using MATLAB for the calculations and expresses a preference for not doing the work by hand for the assignment.
  • A later reply comments on the perceived laziness of the participant who prefers MATLAB.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the best approach, with differing opinions on whether to use Laplace Transforms or differential equations, and the discussion remains unresolved.

Contextual Notes

Some assumptions about the transfer function and the specific parameters involved in the RLC circuit are not detailed, which may affect the discussion.

ankh
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This is more of a math question but i feel like i will get more help among Electrical Engineers.

I successfully found the step response of an RC circuit in the time domain using Laplace Transforms.

But i can't seem to figure out how to do it with an RLC transfer function.

I have the following transfer function for a series RLC with a step input:

http://img201.imageshack.us/my.php?image=38900900ag5.png

a push in the right direction would be appreciated.

cheers
 
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I suggest that you unwind your Laplace transforms and write the description again as a differential equation. You will then need to find homogeneous and particular solutions to the differential equation. In engineering terminology, these are often called the transient and steady state solutions for the differential equation. But the first step is to back away from the Laplace transforms and go back to differential equation notation and thinking.
 
ye lol i just used matlab

syms s
C=...equation..
c=ilaplace(C)

if anyone wants to post how to do it by hand, go ahead. I don't need to do it by hand for this particular assignment.

Thanks for help. I do see now how to do it band nut i am to lazy to do it.
 
Evidently lazy is the operative word here.
 

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