RLC Locus Diagrams Homework: Solve for Z,Y Variables

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SUMMARY

The discussion focuses on solving for the port impedance (Z) and port admittance (Y) in a series circuit with resistance (R) and capacitance (C) at 50Hz. The correct formulas established are Z = R - jX and Y = G + jB, with G and B defined as G = R/(R² + X²) and B = X/(R² + X²). The solution involves completing the square to derive a circular locus with the center at (0, -1/2x) and a radius of -1/2x, demonstrating the relationship between R, X, G, and B as R varies from 0 to infinity.

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Homework Statement

In a series circuit V = V<0 @50hz with an R and C, show that the graph of the loci or the port impedance, Z, and port admittance, Y, as the resistance R is varied from 0 to inf ohms are as shown.
[URL]http://ivila.net/prob.png[/URL][URL]http://ivila.net/loci.png[/URL]

Homework Equations


The Attempt at a Solution



Z = R + j*X;
Y = Z-1;

Map to Y = G + jB (Separate Real and Complex)
G = R/(R2 + X2);
B = -X/(R2 + X2);

G2 + B2 = 1/(R2+X2) = B/-X

Then I get lost,

I know I need to arrange into the format below with the condition that the R term (varying from 0 to inf) remains in the LHS, ie, out of the radius. however I am stuck .
(G-x)2 + (B-y)2 = radius2

Any help would be much appreciated.
 
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I found the solution!

Firstly.

Z = R - jX (incorrectly stated in my first post)
Y = G + jB
G = R/(R^2 + X^2)
B = X/(R^2 + X^2)
G^2 + B^2 = 1/(R^2 + X^2) this is very close to B, infact B/X = G^2 + B^2

using this we can say.

G^2 + B^2 = 1/X * B
G^2 + (B^2 - B/X) = 0

Now Complete the Square

G^2 + (B^2 - B/X + a^2) = a^2
2a = -1/x, a = -1/2x

Therefore

(G^2) + (B + -1/2x)^2 = (-1/2x)^2

or, a circle, origin at 0,-1/2x radius -1/2x

Thanks!
Alex
 

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