RMS Current in Circuit with Capacitor, Inductor, Resistor, AC Source

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SUMMARY

The discussion focuses on calculating the root mean square (RMS) current in a circuit comprising a capacitor, inductor, resistor, and an AC source. Initial measurements indicate an RMS current of 25.1 mA with just the capacitor connected, 15.7 mA when the capacitor is in series with the resistor, and 68.2 mA when in series with the inductor. The final query seeks to determine the RMS current when all four components are connected in series, utilizing the formula Irms = ΔVrms/Z, where Z is the impedance calculated as Z = √(R² + (XL - XC)²).

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Four circuit elements—a capacitor, an inductor, a resistor, and an AC source—are connected together in various ways.
First the capacitor is connected to the source, and the rms current is found to be 25.1 mA. The capacitor is disconnected and discharged, and then connected in series with the resistor and the source, making the rms current 15.7 mA. The circuit is disconnected and the capacitor discharged. The capacitor is then connected in series with the inductor and the source, making the rms current 68.2 mA. After the circuit is disconnected and the capacitor discharged, all four circuit elements are connected together in a series loop.
What is the rms current in the circuit?

i was thinking to use the following: [tex]I_{rms}=\frac{\Delta V_{rms}}{Z}[/tex] where Z is the impedance given by [tex]Z=\sqrt{R^2 + (X_L-X_C)^2[/tex], however i don't have the root mean square voltage...

any hints on how to approach this problem... thanks
 
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just a shot in the dark... it's late here...
start with an assumption of a unity driving signal... one volt rms and one Hz. i'd bet that in the end the frequency and voltage drop out of the final solution.
 

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