Roll 12 different dice. How many will have at least each 1,2,3,4,5,6 occurring?

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Homework Help Overview

The problem involves rolling 12 different dice and determining how many outcomes will include at least one occurrence of each number from 1 to 6. The context is rooted in probability and combinatorial reasoning.

Discussion Character

  • Exploratory, Conceptual clarification, Probability reasoning

Approaches and Questions Raised

  • Participants are attempting to clarify the question's intent, with one expressing uncertainty about whether it pertains to the number of rolls needed to achieve the desired outcome. Others are discussing the total number of outcomes when rolling the dice and considering how to count those that meet the criteria of having at least one of each number.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some have suggested that it is a probability question, while others are working through the implications of rolling multiple dice and the combinations involved.

Contextual Notes

There is some confusion regarding the phrasing of the problem and what is being asked, particularly about the relationship between the number of rolls and the outcomes. Participants are also considering the basic probabilities associated with rolling standard dice.

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Homework Statement


12 different dice are rolled. How many outcomes will have at least one of each number 1,2,3,4,5,6 occurring?

The Attempt at a Solution


I don't even know where to go because I really don't know what the question is asking. Does it mean how many rolls (where each roll is rolling 12 dice) must be made to get at least one of each number?

Thanks
 
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You roll 12 dice.

Each (standard) die has 6 sides. You roll one die, it has 6 different outcomes. You then roll the second die, it has 6 outcomes. For the first two die, you could have 1-1, 1-2, 2-1, 2-2, 3-1, 3-2, 3-3, 2-3, 1-3, etc.

So, after rolling all 12 dice, you have 12*6 possibilities in total.

In how many of those possibilites will you have at least one die being a 1, one being a 2, one being a 3, 4, 5, 6..?
 
It seems to me like a probability question...

Since there are six numbers possible on a dice, and you have have 12 dices, the chances for any of those numbers(1,2,3,4,5, or 6) to come on a single dice is 1/6(<-- fraction). Can you figure out the rest?
 
pretty close goldenwing, 2 minutes difference(between my answer and yours) :)

Although your answer seems to be more comprehensible and better...
 

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