1. The problem statement, all variables and given/known data Two bicycle tires are set rolling with the same initial speed of 3.30m/s along a long, straight road, and the distance each travels before its speed is reduced by half is measured. One tire is inflated to a pressure of 40 psi and goes a distance of 17.3m ; the other is at 105 psi and goes a distance of 93.0m . Assume that the net horizontal force is due to rolling friction only and take the free-fall acceleration to be g = 9.80m/s2 What is the coefficient of rolling friction μr for the tire under low pressure? 2. Relevant equations Fx=ma Fx=μn n=mg v2=v02+2a(x−x0) 3. The attempt at a solution First I solved for the acceleration: 1.65^2 = 3.3^2 + 2a(17.3) a= -.24 Then I set Fx=ma and Fx=μn to be equal, and substituted n=mg in for n ma=μmg The masses cancel out so I get a=μg I tried solving for this -.24=u(9.8) and got -.024, but this answer was incorrect. I feel good about this process but don't know I'm doing wrong? I found another question exactly like this on here but when I tried to do the calculations for acceleration I kept getting a different number, so I don't know if that's where my problem lies but if so I don't understand how my math is wrong.