Rolling without slipping, theory

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HaoPhysics
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Homework Statement


I am solving a question that asks for, what's the minimum coefficient of friction required for a cylinder to roll without slipping? Where the cylinder has a force F acting on its center.
upload_2017-5-6_19-1-53.png

Homework Equations


upload_2017-5-6_18-58-1.png

And
upload_2017-5-6_18-58-31.png


The Attempt at a Solution


From the way I understand it, the only torque acting on the cylinder is the torque from friction, since the torque from force F is acting at the center, thus resulting in 0 torque.

But the resource I'm looking at assumes that torque from friction is not the only torque acting on the cylinder. But it doesn't explain why.

Where are the other torques acting from?
 
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BvU said:
Your problem statement may be incomplete. Zero is the answer as it is written now.
Oops! Yeah I changed it.
 
HaoPhysics said:
But the resource I'm looking at
Tell us what you see. Our telepathic capabilities are limited.

And: what do you do with the given 'rolling without slipping' ?
 
BvU said:
Tell us what you see. Our telepathic capabilities are limited.

And: what do you do with the given 'rolling without slipping' ?

http://www.feynmanlectures.info/solutions/roll_without_slipping_sol_1.pdf
On step 6, it says, "In order for the ball not to slip, the torque on the ball from friction can not be less than the total torque on the ball when it rolls"
(Note: I tweaked the problem from a slope to a flat ground for simplification purposes, so I don't have to worry about the theta for now)

Well since it is rolling without slipping, the linear acceleration must equal to angular acceleration multiplied by radius:
upload_2017-5-6_19-37-21.png


So since the sum of torques is the torque from friction:
upload_2017-5-6_19-43-13.png


Is this correct then?

(Sorry about the really big pictures)
 

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haruspex said:
Retry that last step.

upload_2017-5-6_19-49-45.png


:doh:
 
haruspex said:
That's better. But see the edit I made to my previous post.
Hm..

The only substitution which I can make is this:
upload_2017-5-6_20-11-35.png


I am not sure how to get R in there.
It seems that the coefficient of fric. is not dependent on R.

Interesting, this follows:

upload_2017-5-6_20-17-9.png
 
haruspex said:
No, acm is not F/M.

As I wrote, a subset of those variables is fine. It just must not involve any variables outside of the given set.
Oops! acm is net force / m,

upload_2017-5-7_11-30-26.png
 

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