How Do You Calculate the Acceleration of a Weight and Tension in a Yo-Yo System?

  • Thread starter Thread starter lehel
  • Start date Start date
  • Tags Tags
    Rolling Weight
Click For Summary
SUMMARY

The discussion focuses on calculating the acceleration of an 8lb block and the tension in a 16lb yo-yo system. The key findings indicate that the acceleration of the block is 4.830 ft/s² and the tension in the cord is 6.792 lb. The equations utilized include F = ma, torque = I*alpha, and the moment of inertia calculations involving the radius of gyration. The relationship between the accelerations of the weight and the yo-yo is established as a-weight = a-yo-yo - R*alpha.

PREREQUISITES
  • Understanding of Newton's second law (F = ma)
  • Knowledge of torque and moment of inertia concepts
  • Familiarity with rotational dynamics and angular acceleration
  • Basic algebra for solving equations with multiple variables
NEXT STEPS
  • Study the relationship between linear and angular acceleration in rotational systems
  • Learn about moment of inertia calculations for different shapes
  • Explore the dynamics of pulley systems in physics
  • Investigate advanced applications of torque in mechanical systems
USEFUL FOR

Students in physics or engineering courses, particularly those focusing on mechanics, as well as educators looking to enhance their understanding of rotational dynamics and problem-solving techniques in real-world applications.

lehel
Messages
15
Reaction score
0

Homework Statement


a 16lb yo-yo is resting on a horizontal table and is free to roll. The dimensions are r = 4in and R = 12in and the radius of gyration about the CM is 6in. A cord is wrapped around the inner radius, the passes over a perfect pulley, and is attached to a 8lb block.

Find acceleration of 8lb block and the tension in the cord

(answers are 4.830ft/s^2 and 6.792lb)

Homework Equations



F = ma
torque = I*alpha = F*moment-arm
Iaxis = Icm + mh^2
I = (radius-gyration)R^2




The Attempt at a Solution



there are two accelerations a1 (weight) and a2 (yo-yo).

(16/32slugs)*a2 = T

I at table contact point = 90slug*in^2

net torqe at table contact point = 90slug*in^2 * alpha = T(12in - 4in)

T = 11.25*alpha and 0.5slugs * a2 = T

for weight, (8/32slugs)a1 = 8lb - T

so far, I have 4 unknowns and 3 equations so I can't solve for anything. What equation am I missing? i don't know how to find a relationship between alpha and a2 (i thought a2 = 12in*alpha but that doesn't work out right).

thanks in advance
 
Physics news on Phys.org
Consider pure rotation about axis passes through contact point. the center of mass is 12 in from contact point.
 
i found out what i was missing: an equation describing the relationship between the acceleration of the weight and the acceleration of the yo-yo.

a-weight = a-yo-yo - R*alpha.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
4K
Replies
4
Views
2K
Replies
10
Views
4K
Replies
1
Views
3K
Replies
6
Views
10K
Replies
37
Views
10K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 35 ·
2
Replies
35
Views
5K
  • · Replies 16 ·
Replies
16
Views
5K
Replies
2
Views
4K