Roots of a equation with complex numbers

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Homework Help Overview

The discussion revolves around finding the roots of a quadratic equation involving complex numbers, specifically the equation x^2 - (2-1)x + (3-i) = 0.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants inquire about the notation used in the equation, questioning the expression "(2-1)x" and suggesting it might be a misrepresentation of "(2-i)x". There is also a focus on the application of the quadratic formula and the challenges associated with taking the square root of complex numbers.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the equation's setup and the formula to be used. There is an emphasis on understanding the notation and the correct application of the quadratic formula, but no consensus has been reached yet.

Contextual Notes

Participants are navigating potential misunderstandings in the equation's formulation and the implications of working with complex numbers in the context of the quadratic formula.

subopolois
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Homework Statement


how do i find the roots of this: x^2-(2-1)x+(3-i)=0


Homework Equations


-b+-sqrtb^2-4ac/2a (quardaric equation)


The Attempt at a Solution


 
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What have you done so far?

And why did you write it as "(2-1)x" and not "x"? Did you mean "(2-i)x" instead? Why can't you just apply the formula?
 
Defennder said:
What have you done so far?

And why did you write it as "(2-1)x" and not "x"? Did you mean "(2-i)x" instead? Why can't you just apply the formula?

and what formula would that be?
 
subopolois said:
and what formula would that be?

Use the 'quadratic equation'.
 
The quadratic formula that YOU gave in your first post! Be careful about taking the square root. That's the only "hard" part.
 

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