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Roots of a equation with complex numbers

  1. Oct 23, 2008 #1
    1. The problem statement, all variables and given/known data
    how do i find the roots of this: x^2-(2-1)x+(3-i)=0


    2. Relevant equations
    -b+-sqrtb^2-4ac/2a (quardaric equation)


    3. The attempt at a solution
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Oct 23, 2008 #2

    Defennder

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    What have you done so far?

    And why did you write it as "(2-1)x" and not "x"? Did you mean "(2-i)x" instead? Why can't you just apply the formula?
     
  4. Oct 23, 2008 #3
    and what formula would that be?
     
  5. Oct 23, 2008 #4

    Dick

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    Science Advisor
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    Use the 'quadratic equation'.
     
  6. Oct 23, 2008 #5

    HallsofIvy

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    Staff Emeritus
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    The quadratic formula that YOU gave in your first post! Be careful about taking the square root. That's the only "hard" part.
     
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