Angular Acceleration of a Rotating Wheel: Solving a Common Question

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SUMMARY

The discussion focuses on calculating the angular acceleration of a wheel that starts with an angular velocity of 2 rad/s and completes 5 revolutions in 2 seconds under constant angular acceleration. The key formula derived from the problem is (1/2)a(t^2) + v0t = θ, where θ represents the total angle in radians. By substituting the known values, the equation becomes (1/2)a(4) + 2(2) = 10π, which allows for the calculation of the angular acceleration 'a'. The conclusion is that the angular acceleration remains constant throughout the motion.

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Can anyone help me in solving this question?

At t=0, a wheel is rotating about a fixed axis at a constant angular acceleration has an angular velocity of 2 rad/s. Two seconds later it has turned 5 complete revolutions what is the angular acceleration of this wheel??
 
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The question says that the angular acceleration is constant, so why would it have changed two seconds later? Are you sure you were not asked to solve for the angular velocity?
 
I typed the question just as it was written. I am having trouble finding the formula for the solution, maybe it is written wrong??
 
I would say that the first step is to write the angular velocity of the wheel as a function of time. Have you tried to do this at all?
 
cepheid said:
The question says that the angular acceleration is constant, so why would it have changed two seconds later? Are you sure you were not asked to solve for the angular velocity?

The problem didn't say the angular acceleration had changed. It gave the initial angular velocity and the total angle moved in 2 seconds and asked you to calculate the constant angular acceleration.

mickeychief: this is just like straight line acceleration except that you use angles instead of length:
If the accelaration is a, then the velocity after t is at+ v0,where v0 is the initial velocity, and the "distance" moved is (1/2)at2+ v0t. Since you are told that v0= 2 rad/sec and that, with t= 0, the angle ("distance") moved was
"5 complete revolutions"= 5(2pi)= 10pi radians, you have
(1/2)a(4)+ 2(2)= 10pi. Solve for a.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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