Rotation of a Rigid Object about a fixed axis

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SUMMARY

The discussion focuses on calculating the rotational speed of a wheel after a lead weight collides with it. The wheel consists of two thin rods and a metal ring with a mass of 10.00 kg, while the lead weight has a mass of 0.1 kg and an initial speed of 50.0 m/s. The key equations involved are the conservation of angular momentum, represented by L_f = (I_a + I_b)W_f, and the relationship between linear and angular velocity, given by 0.5Iω² = 0.5mv². The solution requires determining the total moment of inertia and applying these principles to find the final angular velocity in revolutions per second.

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Homework Statement


A wheel is comprised of two 50.0 cm long thin rods of negligible mass and a thin metal ring with a mass of 10.00 kg, mounted on a very low friction bearing. A 100 gram lead weight is shot horizontally at the stationary wheel with an initial speed of 50.0 m/s and sticks to the rim of the wheel. What is the rotational speed of the wheel plus lead mass immediately after the collision? Give your answer in revolutions/second.


Homework Equations


L_f=(I_a + I_b)W_f



The Attempt at a Solution


I know of to find the moments of inertia I am just confused about how to find L_f. The bullet would be travelings in a linear momentum not angular. How can i find this value?
 
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I think you should just use conservation of energy.

You can get the total moment of inertia I, the equation 0.5Iω2=0.5mv2 to get ω.
 

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