Rotation of Disc: Calculating Angular Velocity

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Homework Help Overview

The discussion revolves around calculating the angular velocity of a uniform circular disc subjected to a tangential force. The problem involves concepts of rotational dynamics, specifically the moment of inertia and angular acceleration.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the formula relating torque and angular acceleration, questioning the correctness of the provided answer. There are attempts to derive angular velocity using different approaches and formulas.

Discussion Status

Some participants express confidence in the calculations presented, suggesting that the original poster's answer may be correct. There is a focus on verifying the information given and exploring alternative formulas for angular velocity.

Contextual Notes

Participants question the accuracy of the provided answer and the information given in the problem statement, indicating potential discrepancies in the data or assumptions made.

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Homework Statement



A uniform circular disc at rest has mass 10 kg and radius 0.2m. When a force of 10 N is applied tangentially to the disc for 10s, calculate the angular velocity. Given the moment of inertia, I=1/2 mr^2

Homework Equations





The Attempt at a Solution



Using rF=I(alpha) , alpha = 10 rad/s^2 after substituting r=0.2 , m=10 , F=10

Then, using the rotational formulas,

w = w0 + at (w is meant to be omega)

w = 0+ (10)(10) = 100 rad /s

but the answer given is 10 rad/s .
 
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Your answer is correct. Unless you've copied the given information incorrectly, the answer given is wrong.
 
chaoseverlasting said:
Your answer is correct. Unless you've copied the given information incorrectly, the answer given is wrong.

This is the working of the answer.

Iw=rt

where I, the moment of inertia, w=angular velocity, r= the radius, and t the time.

and from here, the angular velocity is evaluated. I haven't seen that formula before.
 
Yeah, your answer is right given that the info is correct

[tex]\omega=\frac{2F}{mr}t[/tex]
 

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