Rotational accel to linear accel

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chloechloe
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Homework Statement


I do not understand how a was solved for. the picture is a sphere rolling down a hill. Asked to solve for a.


Homework Equations


solve for a, use alpha = a/r
ma = mg sin theta - fs; T = fs*r = I*alpha = (2/5)mr^2; fs = (2/5)ma
a = (5/7)g sin theta

I can't see the progression through these steps

The Attempt at a Solution

 
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chloechloe said:
use alpha = a/r
(1) That's the condition for rolling without slipping.
ma = mg sin theta - fs;
(2) That's Newton's 2nd law applied to translation.
T = fs*r = I*alpha = (2/5)mr^2;
This is an attempt to apply Newton's 2nd law to rotation, but alpha was left out of the right hand term. It should be:
(3) T = fs*r = I*alpha = (2/5)mr^2*alpha
fs = (2/5)ma
(4) Combine 1 and 3 to get this.
a = (5/7)g sin theta
Combine 4 with 2 to get this.
 
Thank you. Makes sense now. I was getting stuck at combining things at the end. The missing alpha didn't help either.