Rotational accel to linear accel

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SUMMARY

The discussion focuses on deriving the linear acceleration (a) of a sphere rolling down a hill using the relationship between rotational and linear motion. The key equation derived is a = (5/7)g sin theta, where g represents gravitational acceleration and theta is the angle of the incline. The participant clarifies the application of Newton's second law for both translation and rotation, emphasizing the importance of the rolling condition (alpha = a/r) and the correct incorporation of torque (T) in the equations. The discussion concludes with a resolution of confusion regarding the combination of equations.

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  • Understanding of Newton's laws of motion
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  • Knowledge of the concept of rolling without slipping
  • Basic trigonometry, particularly sine functions
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  • Learn about the moment of inertia for various shapes, specifically spheres
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Homework Statement


I do not understand how a was solved for. the picture is a sphere rolling down a hill. Asked to solve for a.


Homework Equations


solve for a, use alpha = a/r
ma = mg sin theta - fs; T = fs*r = I*alpha = (2/5)mr^2; fs = (2/5)ma
a = (5/7)g sin theta

I can't see the progression through these steps

The Attempt at a Solution

 
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chloechloe said:
use alpha = a/r
(1) That's the condition for rolling without slipping.
ma = mg sin theta - fs;
(2) That's Newton's 2nd law applied to translation.
T = fs*r = I*alpha = (2/5)mr^2;
This is an attempt to apply Newton's 2nd law to rotation, but alpha was left out of the right hand term. It should be:
(3) T = fs*r = I*alpha = (2/5)mr^2*alpha
fs = (2/5)ma
(4) Combine 1 and 3 to get this.
a = (5/7)g sin theta
Combine 4 with 2 to get this.
 
Thank you. Makes sense now. I was getting stuck at combining things at the end. The missing alpha didn't help either.
 

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