1. The problem statement, all variables and given/known data You have your bicycle upside-down for repairs. The front wheel is free to rotate and is perfectly balanced except for the 16 g valve stem. If the valve stem is 34 cm from the rotation axis and is located 32 degrees below the horizontal, what is the resulting torque about the wheel's axis? (torque = N*m) 2. Relevant equations torque = rFsin(theta) torque = I(alpha) torque = MR^2(alpha) 3. The attempt at a solution So I thought that torque = rFsin(theta) would be the most relevant since I think I know the radius, force, and the theta, giving me: torque = rFsin(theta) torque = r(mg)sin(theta) torque = (.34cm)(0.016kg * 9.8m/s^2)(sin32) = 0.02825 N*m But this is wrong. What did I do wrong?