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Rotational Energy and Moment of Inertia of a nitrogen molecule

  1. Mar 27, 2008 #1
    Problem 10-58a: The equilibrium separation between the nuclei of the nitrogen molecule (N2) is 0.190 nm and the mass of each nitrogen nucleus is 14.0 u, where u = 1.66E-27 kg. For rotational energies, the total energy is due to rotational kinetic energy. Approximate the nitrogen molecule as a rigid dumbbell of two equal point masses and calculate the moment of inertia about its center of mass.

    Calculate the rotational energy levels for l = 1 and l = 2 using the relation El = l(l+1)hbar2/(2/I).

    Anyone have any suggestions on how to tackle this problem?
  2. jcsd
  3. Mar 28, 2008 #2

    Shooting Star

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    It seems to be an extremely simple problem Where are you getting stuck, actually?

    The MI of a point mass about a given point at a distance r is mr^2. The CM of the two point masses here is obviously at the midpoint of the segment joining the the two masses.
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