Rotational energy of diatomic molecule

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SUMMARY

The discussion centers on the rotational energy of a diatomic molecule modeled as two atoms connected by a massless rod. The equation for rotational energy is established as 1/2*m*r^2*(omega(1)^2+omega(2)^2), where 'm' represents the reduced mass, 'r' is the rod length, and 'omega(1)' and 'omega(2)' are the rotational velocity components. The moment of inertia for this system is defined as m*L^2, indicating that the molecule rotates about an axis through its center of mass. The conversation also touches on calculating kinetic energy from atomic vibrations when the molecule is not rotating.

PREREQUISITES
  • Understanding of rotational dynamics and moment of inertia
  • Familiarity with the concept of reduced mass in two-body systems
  • Basic knowledge of harmonic oscillators and molecular vibrations
  • Proficiency in classical mechanics equations related to kinetic and potential energy
NEXT STEPS
  • Study the derivation of the reduced mass formula in diatomic systems
  • Learn about the calculation of moment of inertia for various molecular geometries
  • Explore the relationship between rotational and vibrational energy in diatomic molecules
  • Investigate the principles of harmonic motion in molecular vibrations
USEFUL FOR

Students and professionals in physics, particularly those focusing on molecular dynamics, chemists studying molecular interactions, and educators teaching classical mechanics concepts.

nikolafmf
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Hi,

I consider harmonic model of diatomic molecule: two atoms connected with a massless rod. Let one axis be along the rod, other two perpendicular to it. Let rotational velocity have components only trough perpendicular axes. In one book it is said that rotational energy of such diatomic molecule is 1/2*m*r^2*(omega(1)^2+omega(2)^2), where m is reduced mass, r is the length of the rod, omega(1) and omega(2) are the components of the rotational velocity.

Where this reduced mass come from? How can I derive this equation? I would appreciate any help.


Nikola
 
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What is the moment of inertia of a diatomic molecule about an axis passing through the center of mass?
 
Gokul43201 said:
What is the moment of inertia of a diatomic molecule about an axis passing through the center of mass?

First, thank you for your question which led me to the answer :).

The moment of inertia is m*L^2. So, when calculating rotational energy, author implicitely assumes that molecule rotates about an axis passing through its center of mass and is perpendicular to line conecting atoms. Why should be so? Why not another axis?

Conected with this problem is calculating kinetic energy of the molecule due its vibration. Let say that molecule doesn't rotate, its center of mass doesn't move, but only atoms move to and from each other (they vibrate). We know the mass of each atom and their relative velocity (but not their absolute velocity). How could I calculate kinetic energy due to this motion?
 

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