Rotational Motion- Pulleys with Friction

[danield]

Homework Statement

Two Masses are suspended from a pulley. The pulley itself has a mas of .20kg a radius of .15m a constant torque of .35 MN due to the friction between the rotating pulley and its axle. What is the magnitude of the acceleration of the suspended masses if m1= .4kg and m2= .8 kg (neglect the mass of the string)
Pulley
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M2 M1

Homework Equations

T1= M1G - M1A
T2= M2G + M2A
Torque= FL = Moment of Inertia x Alpha,
I= 1/2 mr^2

The Attempt at a Solution

I have tried solving this by solving for A when T2-T1= I alpha, but i really don't know how to apply the fact that the tension is different of both cords due to the friction on the pulley I am stuck...

 

[danield]

I have tried everything... but still i can't get to the answer.. i get to the formula a=(m2-m1)g/(1/2M+m1+m2) but after that i don't know how to apply the torque... :( need help

 

[danield]

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