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Rotational Motion Tension at the bottom of the circle

  1. Oct 31, 2011 #1
    1. The problem statement, all variables and given/known data

    9. A 0.61 kg mass attached to the end of a 0.50 m cord rotates in a vertical circle. The angular speed of the mass at the bottom of the circle is 2π rad/s. The tension in the string at this point is:

    a. 18 N

    b. 21 N

    c. 12 N

    *d. 54 N

    2. Relevant equations

    W=mg
    F=ma
    acentripetal=v2/r
    v=ωr


    3. The attempt at a solution

    I used Ftension=Fcentripetal+W and I got 18N the answer key says its 54N
     
  2. jcsd
  3. Oct 31, 2011 #2

    Andrew Mason

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    Science Advisor
    Homework Helper

    I agree with your answer.

    AM
     
  4. Oct 31, 2011 #3
    Same here. I think the supplied answer is incorrect.
     
  5. Oct 31, 2011 #4
    Thanks :)
     
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