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Rotational Motion Tension at the bottom of the circle

  • Thread starter physgrl
  • Start date
  • #1
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Homework Statement



9. A 0.61 kg mass attached to the end of a 0.50 m cord rotates in a vertical circle. The angular speed of the mass at the bottom of the circle is 2π rad/s. The tension in the string at this point is:

a. 18 N

b. 21 N

c. 12 N

*d. 54 N

Homework Equations



W=mg
F=ma
acentripetal=v2/r
v=ωr


The Attempt at a Solution



I used Ftension=Fcentripetal+W and I got 18N the answer key says its 54N
 

Answers and Replies

  • #2
Andrew Mason
Science Advisor
Homework Helper
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329
I agree with your answer.

AM
 
  • #3
1,198
5
Same here. I think the supplied answer is incorrect.
 
  • #4
138
0
Thanks :)
 

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