Rotational Motion Tension at the bottom of the circle

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Homework Help Overview

The problem involves a mass rotating in a vertical circle and focuses on calculating the tension in the cord at the bottom of the circle, given specific parameters such as mass, cord length, and angular speed.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the relationship between tension, centripetal force, and weight but arrives at a different answer than the provided solution. Some participants express agreement with the original poster's calculation, questioning the accuracy of the answer key.

Discussion Status

The discussion is currently exploring differing interpretations of the problem, with participants questioning the correctness of the answer key. There is no explicit consensus on the solution, but there is a shared skepticism regarding the provided answer.

Contextual Notes

Participants are operating under the assumption that the answer key may contain an error, and there is a lack of clarity regarding the application of the relevant equations in the context of the problem.

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Homework Statement



9. A 0.61 kg mass attached to the end of a 0.50 m cord rotates in a vertical circle. The angular speed of the mass at the bottom of the circle is 2π rad/s. The tension in the string at this point is:

a. 18 N

b. 21 N

c. 12 N

*d. 54 N

Homework Equations



W=mg
F=ma
acentripetal=v2/r
v=ωr

The Attempt at a Solution



I used Ftension=Fcentripetal+W and I got 18N the answer key says its 54N
 
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I agree with your answer.

AM
 
Same here. I think the supplied answer is incorrect.
 
Thanks :)
 

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