In this case A cannot be in a state that do not satisfies the properties of its parts, and this it exactly what I say.
Then you have to prove it. You have to prove that A satisfies the condition required to be a member of A.
The set of all dogs is not a dog itself but it has a common property with each dog that included in it, which we can call it "Dogness".
Can you show one example of "dogness" that is shared by "the set of all dogs"?
1) Please show us how a set can get its name (identity) without any relation to the properties of its contents.
"The set of all dogs" gets is name precisely because:
(1) every dog is contained in the "set of all dogs"
(2) everything in the "set of all dogs" is a dog
There is no reason to think that the "set of all dogs" should have any properties of dogs. The relation here is:
A thing is a member of the "set of all dogs" if and only if that thing is a dog.
But, finally, "the set of all dogs" doesn't need to have a name; it can be discerned completely by the two properties I listed above.
In fact, pay attention to the fact that the name "the set of all dogs" is not really a name at all; it is a phrase stating what objects are in the set!
Speaking loosely, the "identity" of a set is
entirely determined by the identities of its contents. This is stated in the axioms of ZFC by "A and B are the same set if and only they have the same elements".
By the way, to say that a set is not its members is a non-abstract and trivial thing to say.
You have this
exactly backwards. A set is an abstract thing, whose "identity" is given entirely by the concept of "membership". The fact that you are unwilling (unable?) to separate the two ideas "properties of a set" and "properties of the elements of a set" is a very strong indicator of non-abstract thinking.