Rutherford Scattering cross section

1. Apr 14, 2010

SuperPokenerd

1. The problem statement, all variables and given/known data
Integrate the rutherford cross section over the backward hemisphere to get 4pi(sigma0(E))

2. Relevant equations

Rutherford cross section is sigma0(E)/sin^4(theta/2)

3. The attempt at a solution
When I integrate this with the limits pi/2 to pi i get sigma0(E)*(8/3) i don't know what i'm doing wrong.

2. Apr 14, 2010

NeoDevin

Are you sure you have your integration limits correct?

3. Apr 14, 2010

SuperPokenerd

I thought so, since the problem says that theta goes between pi/2 and pi i.e. large angle scattering is from 90-180 degrees. I don't see how i'm supposed to get it to be 4pi instead of 8/3.

4. Apr 14, 2010

NeoDevin

Never mind my previous response, I was confusing this with a different problem I was solving earlier.

As near as I can tell, your solution appears to be correct.