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Rutherford Scattering cross section

  1. Apr 14, 2010 #1
    1. The problem statement, all variables and given/known data
    Integrate the rutherford cross section over the backward hemisphere to get 4pi(sigma0(E))

    2. Relevant equations

    Rutherford cross section is sigma0(E)/sin^4(theta/2)

    3. The attempt at a solution
    When I integrate this with the limits pi/2 to pi i get sigma0(E)*(8/3) i don't know what i'm doing wrong.
  2. jcsd
  3. Apr 14, 2010 #2
    Are you sure you have your integration limits correct?
  4. Apr 14, 2010 #3
    I thought so, since the problem says that theta goes between pi/2 and pi i.e. large angle scattering is from 90-180 degrees. I don't see how i'm supposed to get it to be 4pi instead of 8/3.
  5. Apr 14, 2010 #4
    Never mind my previous response, I was confusing this with a different problem I was solving earlier.

    As near as I can tell, your solution appears to be correct.
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