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Physics
High Energy, Nuclear, Particle Physics
S-Channel Process: a+b->c+d Diagrams
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[QUOTE="nrqed, post: 5471986, member: 15416"] If you are working with time-ordered diagrams, things are different than with usual Feynman diagrams. One of the time ordered diagrams is the one you have in mind. For the second, a and b annihilate into a photon (or whatever you are dealing with), this photon travels then the left (it travels "back in time") and then it produces c and d. In other words, in time ordered diagrams, the time ordering of the vertices is crucial, having the vertex "a+b to a photon" before the vertex "photon to c+d" is different from the other ordering. The usual Feynman diagram combines these two into a single expression. [/QUOTE]
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Physics
High Energy, Nuclear, Particle Physics
S-Channel Process: a+b->c+d Diagrams
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