Greetings, Kindly, may I have my answers checked, please. 1. The problem statement, all variables and given/known data d. A 40kg child sits on a swing of length 8.0m and is swinging with a maximum displacement of 2.0m from the equilibrium position. If the motion can be considered to be SHM, calculate the: i. Period of the swing. ii. Maximum vertical distance the child rises above the equilibrium position iii. Maximum velocity of the child during the motion iv. The total energy produced due to this motion 2. Relevant equations i. T = 2π√l/g ii. x = rsinwt iii. V = coswt iv. (Kinetic Energy) Ek = 1/2mv² 3. The attempt at a solution i. From T = 2π√l/g = 2πw, we see that w = √g/l = √9.8/1 = 9.8, assuming g = 9.8 m/s ² T = √ 2π/9.8 = 0.8 s ii. x = rsinwt w = 2πf f = 1/0.8 = 0.25 Hz w = 2π x 1.25 = 7.85 1/rads x = 2m x sin7.85 1/rads x 0.8 = 1.6 iii. V = wrcoswt = 0.8 1/rads x 2π x cos7.851/rads x 0.8 = 0.02 m/s iv. Ek = 1/2mv² = 40 x (0.02)²/2 = 0.008 J QUESTION 2 In a harbour, the equation for the depth h of water is h = 5.0 + 3.0sin(2π/45600) where h is given in metres and t is the time in s. (The angle 2πt/45600 is in radians) For this harbour, calculate: i. the maximum depth of water 5.0 + 3.0 = 8.0 m ii. the minimum depth of water = 5.0 m iii. the time interval between high and low-water iv. two values of t at which the water is 5.0m deep v. the length of time for each tide during which the depth of water is more than 7.0 m. I don't understand iii, iv v. May I have some hints on how to approach them please.