Simple harmonic motion oscillate. What is the total energy

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SUMMARY

The total energy of a 50 g oscillating mass described by the position function x(t)=(2.0cm)cos(10t−π/4) is calculated using the formula for maximum potential energy, yielding a result of 0.001 J. The period T is determined to be 0.6283 s using T = 2π/w, where w is the angular frequency of 10 rad/s. The spring constant k is derived as 5.000 N/m using the mass and the period. The discussion highlights that maximum kinetic energy can also be used to find total energy, reinforcing the equivalence of kinetic and potential energy in simple harmonic motion.

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Homework Statement


The position of a 50 g oscillating mass is given by x(t)=(2.0cm)cos(10t−π/4), where t is in s. If necessary, round your answers to three significant figures. Determine: The total energy.

Homework Equations


T = 2π/w
T = 2π√m/k
1/2kA^2
1/2mv^2
1/2kx^2

The Attempt at a Solution


T = 2π/10 = 0.6283s
k = 0.5kg / (0.6823/2π)^2 = 5.000N/m
1/2kA^2 = 0.5(5)(0.02)^2 = 0.001J
 
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Your answer is right.

In my opinion, it's more straightforward to find the answer from the maximum kinetic energy. Find the amplitude of dx/dt, which is the maximum velocity, which can be used to find the maximum kinetic energy (which equals the total energy because at that moment there's no potential energy).

But whichever way you like best is good.
 
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