atay5510
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Homework Statement
A valve for a pressure system has a discharge hole whose diameter is 50mm. The spring has a free length of 250mm (if you stretched the spring out), a coiled length (measured top to bottom while spring is coiled) of 207mm and a spring constant of 120kN/m. At what pressure will the valve open?
Homework Equations
Not 100% but I think
a) p = F/A
b) F = kx
The Attempt at a Solution
Area of discharge hole = ∏r2 = 1.963x10-3m2
Force exerted by spring to keep hole closed = length of spring x spring constant = .207m x 120kN/m = 24.84kN
Therefore valve open pressure = 24.84kN/1.963x10-3m2 = 12.65 kPa.
How does that look? There is a diagram with some other info attached but I'm not sure it's relevant.
Thanks!