Sagging Bottom Quantum Box and Pertubation

TFM
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Homework Statement



Consider a particle in a one-dimensional “box” with sagging bottom

[tex]v(x) = -V_0sin(\pi x/L) for 0 \leq x \leq L[/tex]

infinity outside of thius (x > L, x < 0)

a)

Sketch the potential as a function of x.

b)

For small [tex]V_0[/tex] this potential can be considered as a small perturbation of a “box” with a straight bottom, for which we have already solved the Schrödinger equation. What is the perturbation potential [tex]\Delta[/tex]V (x)?

c)

Calculate the energy shift due to the sagging for the particle in the nth stationary state to first order in the perturbation.

Homework Equations





The Attempt at a Solution



I have completed the first section with a graph as attached. I am not sure on the second part. I know for a inharmonic oscillator,

[tex]v(x) = V_0(x) + \lambda x^4[/tex]

where [tex]\lambda x^4[/tex] is the [tex]\Delta v[/tex]

But I am not sure what to do in this question.

Can anyone offer any advice?

Many Thanks

TFM
 

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Okay, I feel that this may too be very useful for this problem

[tex]V(x) = V_0(x) + \Delta V(x)[/tex]

rouble is, this is a sum, where as the V(x) for this question appears to be the product, snce it is [tex]-V_0 * sin(\pi x /L)[/tex]

Also, may be useful, the stationary Schrödinger Equation,

[tex]E_n\phi_n(x) = -\frac{\hbar^2}{2m} + (v_0(x) + \Delta V(x))\phi_n(x)[/tex]

Is this useful?

Any suggestions?

The Ferry Man
 

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