Separation of Variables to Calculate Potential Inside Box

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SUMMARY

The discussion focuses on using separation of variables to calculate the electric potential inside a cubical box with specific boundary conditions in an Introductory E&M course at the University of Alabama in Huntsville. The box consists of four grounded metal plates, with the top and bottom faces held at a constant potential V0. The participants are struggling with the application of boundary conditions and the method referred to as "Fourier's trick" to solve for the potential, particularly due to the complexity introduced by having both the top and bottom plates at potential.

PREREQUISITES
  • Understanding of separation of variables in partial differential equations
  • Familiarity with electric potential and boundary conditions in electrostatics
  • Knowledge of Fourier series and their application in solving boundary value problems
  • Basic concepts of electrostatics and potential theory
NEXT STEPS
  • Study the application of Fourier series in solving boundary value problems in electrostatics
  • Learn about the method of separation of variables in three dimensions
  • Explore the derivation and application of hyperbolic functions in potential problems
  • Review examples of similar electrostatic problems involving multiple boundary conditions
USEFUL FOR

This discussion is beneficial for physics students, particularly those studying electromagnetism, as well as educators and tutors looking for insights into solving complex boundary value problems using separation of variables.

Seraphim755
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My friends and I are in our first senior-level physics course at the University of Alabama in Huntsville, Introductory E&M. At the moment, we're working on using separation of variables to calculate electric potentials inside different objects given certain boundary conditions. One, however, is giving us problems.

1. Homework Statement


A cubical box of side length a consists of four metal plates that are welded together and grounded. The top and bottom faces of the cube are made of separate metal sheets and insulated from the others. These faces are held at a constant potential V0. Find the potential inside the box.

Homework Equations



Standard form for separation of variables for this problem leads to the form:
X(x) = Asin(kx) + Bcos(kx)
Y(y) = Csin(ly) + Dcos(ly)
Z(z) = Ee√(k2+l2)z + Fe-√(k2+l2)z

With variables being changed based on the boundary conditions in the problems, which can be found by considering which plates are grounded. For this particular problem, we believe the boundary conditions to yield:

V = 0 @ x = 0 , x = a
V = 0 @ y = 0 , y = a
V = V0 @ z = 0 , z = a

The Attempt at a Solution


[/B]
We worked a similar problem where only one plate had potential, the top plate. It was fairly straightforward, with the X and Y portions turning into sine functions and the Z portion becoming a hyperbolic sine function thanks to the exponentials. However, we are not sure what to do with this given the bottom plate having potential as well. Our teacher mentioned a method that he referred to as "Fourier's trick" that is a bit much to try to type out. Not sure if this is well-known terminology, but I thought I'd mention it.

Thanks in advance for the help, we deeply appreciate it!
 
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Seraphim755 said:
My friends and I are in our first senior-level physics course at the University of Alabama in Huntsville, Introductory E&M. At the moment, we're working on using separation of variables to calculate electric potentials inside different objects given certain boundary conditions. One, however, is giving us problems.

1. Homework Statement


A cubical box of side length a consists of four metal plates that are welded together and grounded. The top and bottom faces of the cube are made of separate metal sheets and insulated from the others. These faces are held at a constant potential V0. Find the potential inside the box.

Homework Equations



Standard form for separation of variables for this problem leads to the form:
X(x) = Asin(kx) + Bcos(kx)
Y(y) = Csin(ly) + Dcos(ly)
Z(z) = Ee√(k2+l2)z + Fe-√(k2+l2)z

With variables being changed based on the boundary conditions in the problems, which can be found by considering which plates are grounded. For this particular problem, we believe the boundary conditions to yield:

V = 0 @ x = 0 , x = a
V = 0 @ y = 0 , y = a
V = V0 @ z = 0 , z = a

The Attempt at a Solution


[/B]
We worked a similar problem where only one plate had potential, the top plate. It was fairly straightforward, with the X and Y portions turning into sine functions and the Z portion becoming a hyperbolic sine function thanks to the exponentials. However, we are not sure what to do with this given the bottom plate having potential as well. Our teacher mentioned a method that he referred to as "Fourier's trick" that is a bit much to try to type out. Not sure if this is well-known terminology, but I thought I'd mention it.

Thanks in advance for the help, we deeply appreciate it!
Consider the symmetry of Z with respect to z, assuming z = 0 is at the center of the box.

Chet
 
What exactly is the difficulty you're running into?
 

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