Sailboat Acceleration Calculation

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Homework Help Overview

The discussion revolves around calculating the initial acceleration of a sailboat under the influence of wind and water forces. The sailboat's mass is given, along with the wind speed, and participants are exploring the forces acting on the boat.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between wind force and acceleration, with one suggesting to find the force exerted by the wind perpendicular to the sail. Others mention the need to consider the vector nature of forces and how to resolve them into components.

Discussion Status

The discussion is ongoing, with participants providing insights into the forces involved and suggesting methods to approach the problem. There is no explicit consensus yet, but some guidance on resolving forces into components has been offered.

Contextual Notes

Participants are working with the assumption that the wind force is proportional to its perpendicular component, and they are considering the effects of drag and the two-dimensional nature of the forces involved.

DriverX
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Initial Acceleration?

The force exerted by the wind on a sailboat is approximately perpendicular to the sail and proportional to the component of the wind velocity perpendicular to the sail. For the 950-kg sailboat shown in the figure below, the proportionality constant is
da.gif


Water exerts a force along the keel (bottom) of the boat that prevents it from moving sideways, as shown in the figure. Once the boat starts moving forward, water also exerts a drag force backwards on the boat, opposing the forward motion.

If a 15-knot wind (1 knot = 0.514 m/s) is blowing to the east, what is the initial acceleration (m/s2) of the sailboat?

diagram.gif
 
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Welcome to PF!

Hi DriverX! Welcome to PF! :smile:

But … is that picture really a sailboat? :confused:

It looks more like a horse! :biggrin:
 


p4-54.gif
 
that's better! :biggrin:

ok …
DriverX said:
The force exerted by the wind … is … proportional to the component of the wind velocity perpendicular to the sail.

… so find the force exerted by the wind perpendicular to the sail, and so find the forward force, and use F = ma.

What do you get? :smile:
 


Driver
because a force is a vector and the question is in two dimensions, i.e X and Y,
you can separate the force into it's x and y components

e.g if you push a block north east (like your sail) at an angle of 45 degrees
your F vector, is really two forces, one going east in the X direction, and one going north in the Y direction,

so the Feast = Fcos45 degrees
and Fnorth = Fsin45 degrees

you can use this concept (i think? ) to help solve your question
 

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