Salt Shaker on a Lazy Susan, magnitude of force

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SUMMARY

The discussion centers on calculating the magnitude of the horizontal contact force acting on a salt shaker placed on a lazy Susan. Joey spins the turntable, which completes one rotation every two seconds, while the shaker has a mass of 87 grams and is positioned 0.22 meters from the center. The speed of the shaker is determined to be 0.6908 m/s. To find the horizontal contact force, participants need to apply the formula for centripetal acceleration, which is essential for understanding the forces involved in circular motion.

PREREQUISITES
  • Centripetal acceleration concepts
  • Basic physics of circular motion
  • Force calculations using Newton's laws
  • Understanding of mass and weight in physics
NEXT STEPS
  • Study the formula for centripetal acceleration: \( a_c = \frac{v^2}{r} \)
  • Learn how to calculate net force using \( F = m \cdot a \)
  • Explore the relationship between speed, radius, and period in circular motion
  • Investigate the role of friction in maintaining circular motion on a turntable
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Students studying physics, educators teaching circular motion concepts, and anyone interested in practical applications of force and motion in everyday scenarios.

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Mischievous Joey likes to play with his family's lazy susan (this drives Mom crazy because it is an antique). He puts the salt shaker near the edge and tries to spin the tray at a speed so that the shaker just barely goes around without slipping off. Joey finds that the shaker just barely stays on when the turntable is making one complete turn every two seconds. Joey's older sister measures the mass of the shaker to be 87 grams. She also measures the radius of the turntable to be 0.22 m, and she is able to calculate that the speed of the shaker as it successfully goes around in a circle is 0.6908 m/s.

What is the magnitude of the horizontal part of the contact force on the shaker by the turntable?i am so lost, can someone please help me to get this problem started?? i thought i needed to find the acceleration of the salt shaker and used 0 as my starting velocity, but when i went to find the force i didnt come up with the right answer.
 
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A body moving at uniform speed in a circle must have a centripetal acc.
Do you know the expression for this acc?
 

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