Scattering in Finite step potential

Guaicai · Sep 17, 2016

origin page : http://www.physicspages.com/2012/08/08/finite-step-potential-scattering/
No quite understand how the solution

$latex.png$

$Equation (12): (ik + μ)/(ik − μ) A, a fraction multiplied by A, from a finite step potential scattering derivation.$

$latex.png$

$Equation (13): 2ik/(ik - μ) A, a fraction with numerator 2ik and denominator ik minus μ, multiplied by A.$

come from this equation

$latex.png$

$Small equation label reading D (10), likely an equation number beside a scattering equation.$

$Small inline expression ik(A - B) written in italic serif type, with a thin rule underneath.$

$latex.png$

$Equation -μD (11), a single labelled line in a derivation.$

Simon Bridge · Sep 17, 2016

Solve for B and D in terms of A and simplify.

vela · Sep 17, 2016

If you want to solve for B and D in terms of A, you have a linear system with two equations and two unknowns, e.g., x+y=4, 2x-3y=0, but the constants look complicated.

Scattering in Finite step potential

Discussion

Similar threads