Schwartz equation 2.72 field expansion

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John Fennie
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The attached pic is from Schwartz.
Can someone explain the second equality sign in (2.72)?
 
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  • Textbook page titled 2.3.1 Field expansion showing equations 2.68 to 2.72: commutators [a, a†] = 1 and [a_k, a_p†] = (2π)^3 δ^3(p - k), state |p> = a_p†|0> / sqrt(2ω_p), <0|0> = 1, and <p|k> = 2 sqrt(ω_p ω_k) <0|a_p a_k†|0> = 2ω_p (2π)^3 δ^3(p - k).
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John Fennie said:
The attached pic is from Schwartz.
Can someone explain the second equality sign in (2.72)?

Use (2.69) and (2.71).
 
George Jones said:
Use (2.69) and (2.71).
Hi that is my problem. I wasn't able to incorporate (2.69). Is there an idea?
 
Rewrite (2.69) as
$$\left[ a_p , a_k^\dagger \right] = \left(2\pi\right)^3 \delta \left( \vec k - \vec p \right),$$
expand the left side, and use this in (2.72).
 
George Jones said:
Rewrite (2.69) as
$$\left[ a_p , a_k^\dagger \right] = \left(2\pi\right)^3 \delta \left( \vec k - \vec p \right),$$
expand the left side, and use this in (2.72).
Thank you!