Second order frequency response question

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SUMMARY

The discussion centers on solving a second-order frequency response problem involving an RLC circuit. The user struggles with finding an equivalent parallel circuit from a given series configuration that includes a 40kΩ resistor, a capacitor, and an inductor. Suggestions include using Thevenin's and Norton's theorems to simplify the circuit analysis, specifically to split the impedance into parallel components of capacitance and inductance for easier calculations.

PREREQUISITES
  • Understanding of RLC circuit configurations
  • Familiarity with Thevenin's and Norton's theorems
  • Knowledge of impedance calculations in AC circuits
  • Basic circuit analysis techniques
NEXT STEPS
  • Study Thevenin's theorem for circuit simplification
  • Learn about Norton's theorem and its application in circuit analysis
  • Explore impedance splitting techniques for RLC circuits
  • Review mathematical methods for analyzing second-order systems
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing RLC circuits and frequency response characteristics.

Learnphysics
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Homework Statement


http://img534.imageshack.us/img534/9687/rlc.png

Cannot do this question, the first part confuses me when it asks to find an equivalent Parallel circuit.

My first instinct was to try to add the capacitor and inductor and 40k Resistance together to create an RLC series circuit.

From this to add the 40k and the 10k resistances (because they are now in series)... Then we have a circuit with one resistance and one component causing impedance.

From here if we could SPLIT the impedance into both capacitance and inductance, we would have a parallel RLC.



how to mathamatically do the last part (the splitting of a given impedance into a parallel capacitance and inductance) I have no idea.

Or is there a much more simple/elegant way to go about doing this?
 
Last edited by a moderator:
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Have you tried Thevenin equivalent?
 
Learnphysics said:

Homework Statement



Cannot do this question, the first part confuses me when it asks to find an equivalent Parallel circuit.

My first instinct was to try to add the capacitor and inductor and 40k Resistance together to create an RLC series circuit.

From this to add the 40k and the 10k resistances (because they are now in series)... Then we have a circuit with one resistance and one component causing impedance.

From here if we could SPLIT the impedance into both capacitance and inductance, we would have a parallel RLC.
how to mathamatically do the last part (the splitting of a given impedance into a parallel capacitance and inductance) I have no idea.

Or is there a much more simple/elegant way to go about doing this?

I'm not 100% sure about this but couldn't you simply find the Norton equivalent at the terminals of the inductor?

Then you would have a parallel RLC circuit with a current source supplying power as opposed to a voltage source.
 

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