How do I calculate the expected Gain?

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SUMMARY

The discussion focuses on calculating expected gain in AC RLC circuits, specifically addressing the inclusion of internal resistance in series with inductors. The impedance is calculated using the formula Sqrt(R^2 + (Internal R)^2 + (wL - (1/wc))^2). For gain calculation over the inductor, the participant questions whether to sum the components of gain or use a more complex combination, suggesting the equation 20Log((XL + (internal Resistance)) / Z) for dB calculation. The reasoning for series configuration is clarified by noting that the current through the inductor matches that through its internal resistance.

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TL;DR
I am doing an experiment in electronics with AC RLC circuits, But there are a few things about what I need to do that I don't understand.
What is The gain equation for an inductor with internal resistance .
Why is the internal resistance in series.
I am doing an experiment in electronics with AC RLC circuits, But there are a few things about what I need to do that I don't understand.
First: While I know in the circuit diagram we include the internal resistance of the Inductor in series, but I don't know why we include it in series rather than in parallel.
Second: The Magnitude of the impedance should be Sqrt(R^2+(Internal R)^2+(wL-(1/wc))^2,
but what should I be using for the gain over the inductor, since it has two components to its gain should I add them when calculating the dBnof the inductor, or is there a more complicated combination .
I.E should the equation be 20Log((XL+(internal Resistance))/Z)
Thanks for help.
for reference: Capacitative Reactance=Xc. Inductive reactance=XL, resistance=R, Total impedance=Z
 
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We use the internal resistance in series with the (ideal) inductor because the current through the inductor is the same as the current through its internal resistance. When the currents are the same the components are in series.
 

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