Second order homogeneous ODE with vanishing solution

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SUMMARY

The discussion centers on solving a second-order homogeneous ordinary differential equation (ODE) with a vanishing solution. The ODE is defined as y" + y = 1 - t²/π² for 0 ≤ t ≤ π and y" + y = 0 for t > π, with initial conditions y(0) = 0 and y'(0) = 0. The characteristic equation yields roots ±i, leading to a general solution of y = A cos t + B sin t. However, applying the initial conditions results in A and B both equaling zero, indicating a need to match solutions across the defined intervals at t = π.

PREREQUISITES
  • Understanding of second-order ordinary differential equations (ODEs)
  • Familiarity with homogeneous and non-homogeneous ODEs
  • Knowledge of initial value problems and continuity conditions
  • Ability to solve characteristic equations and interpret complex roots
NEXT STEPS
  • Study the method of matching solutions at boundary points in ODEs
  • Learn about the implications of initial conditions on ODE solutions
  • Explore the theory behind complex roots in characteristic equations
  • Investigate the use of Fourier series in solving boundary value problems
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This discussion is beneficial for students and educators in mathematics, particularly those focusing on differential equations, as well as researchers and practitioners dealing with boundary value problems in physics and engineering.

CassieG
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Homework Statement



Solving the linked set of ODEs:

y" + y = 1-t^2/π^2 for 0 ≤ t ≤ π

y" + y = 0 for t > π

We are given the initial condition that y(0) = y'(0) = 0, and it is also noted that y and y' must be continuous at t = π

Homework Equations



See above.

The Attempt at a Solution



The non-homogeneous ODE when t is between 0 and π didn't give me too much trouble, but it's the seemingly simpler homogeneous case for t > π that I'm struggling with: everything seems to go to zero!

The root of the characteristic equation is ±i.

That gives a solution of y = A cos t + B sin t, but using the given initial conditions both A and B are 0.

Thanks for any help you can offer.
 
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The initial conditions don't matter because they're for t=0 and you're looking at the solution for t>pi.

You want to match the solutions in the two regions at t=pi.
 
Ah, thanks, that helps a lot.
 

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