General solution to the differential equation

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SUMMARY

The general solution to the second-order ordinary differential equation (ODE) given by (d²y/dx²) - 2(dy/dx) + y = 0 can be derived using the auxiliary equation method. By substituting the trial solution y = e^(rx), the characteristic equation r² - 2r + 1 = 0 is formed, which has a double root at r = 1. Therefore, the general solution is y = (C1 + C2x)e^x, where C1 and C2 are constants determined by initial conditions.

PREREQUISITES
  • Understanding of second-order ordinary differential equations (ODEs)
  • Familiarity with auxiliary equations and characteristic roots
  • Knowledge of exponential functions and their properties
  • Basic skills in solving differential equations
NEXT STEPS
  • Study the method of solving second-order linear ODEs with constant coefficients
  • Learn about the application of the Wronskian in determining linear independence of solutions
  • Explore the use of Laplace transforms for solving differential equations
  • Investigate initial value problems and their solutions in the context of ODEs
USEFUL FOR

Students of mathematics, engineers, and anyone involved in solving differential equations, particularly those focusing on second-order linear ODEs with constant coefficients.

ZedCar
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Homework Statement


Find the general solution to the differential equation:

(d2y/dx2) - 2(dy/dx) + y = 0

Homework Equations


The Attempt at a Solution



Is my solution correct?

(dy/dx) - 2 + (y^2)/2 + C1 = 0

y - 2y + (y^3)/6 + C1 + C2 = 0

-y + (y^3)/6 + C1 + C2 = 0

y = (y^3)/6 + C1 + C2

Thank you
 
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You have a 2nd order ODE with constant coefficients. You need to firstly solve the auxiliary equation formed when you substitute the trial solution y = erx.
 
ZedCar said:

Homework Statement


Find the general solution to the differential equation:

(d2y/dx2) - 2(dy/dx) + y = 0

I think you ought to be able to recognise that as

(\frac{d}{dx} -1)^2 y =0
 

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