General solution to the differential equation

In summary, the given conversation discusses finding the general solution to a second order ODE with constant coefficients. The suggested method is to solve the auxiliary equation formed by substituting the trial solution y=erx. The final form of the general solution is y = (y^3)/6 + C1 + C2.
  • #1
ZedCar
354
1

Homework Statement


Find the general solution to the differential equation:

(d2y/dx2) - 2(dy/dx) + y = 0

Homework Equations


The Attempt at a Solution



Is my solution correct?

(dy/dx) - 2 + (y^2)/2 + C1 = 0

y - 2y + (y^3)/6 + C1 + C2 = 0

-y + (y^3)/6 + C1 + C2 = 0

y = (y^3)/6 + C1 + C2

Thank you
 
Physics news on Phys.org
  • #2
You have a 2nd order ODE with constant coefficients. You need to firstly solve the auxiliary equation formed when you substitute the trial solution y = erx.
 
  • #3
ZedCar said:

Homework Statement


Find the general solution to the differential equation:

(d2y/dx2) - 2(dy/dx) + y = 0

I think you ought to be able to recognise that as

[tex] (\frac{d}{dx} -1)^2 y =0 [/tex]
 

Related to General solution to the differential equation

1. What is a general solution to a differential equation?

A general solution to a differential equation is a function or set of functions that satisfies the equation and includes all possible solutions. It is often expressed in terms of arbitrary constants, which can take on different values to represent different specific solutions.

2. How is a general solution different from a particular solution?

A particular solution is a specific function that satisfies the differential equation under given initial conditions. It is unique and does not include arbitrary constants. A general solution, on the other hand, includes all possible solutions and can be found by adding any particular solution to a set of solutions to the homogeneous equation.

3. What is the process for finding a general solution to a differential equation?

The process for finding a general solution to a differential equation involves solving the equation using integration, separation of variables, or other methods to find a particular solution. Then, by adding this particular solution to the solutions of the homogeneous equation (which is obtained by setting all terms equal to 0), a general solution can be formed.

4. Can a general solution be expressed in different forms?

Yes, a general solution can be expressed in different forms depending on the method used to solve the equation. For example, a solution to a first-order linear differential equation can be expressed as a power series, as a function of a single variable, or as an explicit function of the independent variable.

5. How can a general solution be verified?

To verify a general solution, it can be substituted into the original differential equation to see if it satisfies the equation. Additionally, the solution can be graphed to visually confirm that it satisfies the equation for various values of the independent variable and initial conditions.

Similar threads

  • Calculus and Beyond Homework Help
Replies
4
Views
956
  • Calculus and Beyond Homework Help
Replies
6
Views
877
  • Calculus and Beyond Homework Help
Replies
2
Views
755
  • Calculus and Beyond Homework Help
Replies
20
Views
462
  • Calculus and Beyond Homework Help
Replies
2
Views
871
  • Calculus and Beyond Homework Help
Replies
2
Views
475
  • Calculus and Beyond Homework Help
Replies
2
Views
350
  • Calculus and Beyond Homework Help
Replies
12
Views
1K
  • Calculus and Beyond Homework Help
Replies
3
Views
917
  • Calculus and Beyond Homework Help
Replies
2
Views
564
Back
Top