- #1
Zack K
- 166
- 6
If we have a conservative vector field, then we can describe it as ##\textbf{F}=\nabla\phi## where ##\phi## is some potential.
This here is the derivation of Newtons law of gravity:
Where ##\nabla u## is the gravitational potential. If we were to ignore it as a gravitational field, why is it force per unit mass? Should it not be the same expression as an arbitrary conservative field?
This here is the derivation of Newtons law of gravity:
Where ##\nabla u## is the gravitational potential. If we were to ignore it as a gravitational field, why is it force per unit mass? Should it not be the same expression as an arbitrary conservative field?