Selecting a Suitable S275 Steel Universal Beam Section

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Discussion Overview

The discussion revolves around selecting a suitable S275 steel universal beam section for a floor beam application, considering imposed and dead loads, as well as the structural requirements for the beam. The scope includes technical calculations related to structural engineering.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • The original poster presents calculations for imposed load and dead load to determine a suitable universal beam section.
  • Some participants propose that the calculations appear correct based on the information provided.
  • One participant questions whether the self-weight of the steel beam has been accounted for in the calculations.
  • Another participant acknowledges the previous comment as a valid observation.

Areas of Agreement / Disagreement

Participants generally agree that the calculations seem correct, but there is a disagreement regarding the consideration of the beam's self-weight, which remains unresolved.

Contextual Notes

There are limitations regarding the assumptions made in the calculations, particularly concerning the self-weight of the steel beam and its impact on the overall design.

thebest99
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steel floor beams span 7.0m and are at 4.2m spacing. the beams are fully laterally restrained by precast concrete floor slabs, 180mm thick, which they support. the floor has to support a speciified imposed load of 5.0 kNm-2.

determine a suitable grade S275 steel universal beam section

From what i have worked out so far:

imposed load = 5.0kNm-2 x 4.2m
=21kN/m

dead load = 4.2m x 0.18m x 24kN/m3
=18.14kN/m
to select a suitable UB section:
214x1.6x7+18.14x1.4x7
=413kN

design shear force:
413/2= 206.5

desing BM:
m=wl sqaured / 8 =

18.14x1.4+21x1.6 x 7sqaured / 8 = 361.4

section selection:
S=m/py

=361.4/275

=1314cm cubed

this is where I am lost need to find UB with plastic section modulus

do i use UB 406 x 178 x 67

if someone could help me with this question and make sure I am doing this example right

thank you
 
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thebest99: I currently think your answer looks correct.
 
I don't see where you have taken account of the self-weight of the steel beam (small as it is).
 
Good catch, pongo38.
 

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