If three one by one squares are selected at random from the chessboard, then the probability that they form the letter 'L' is
The Attempt at a Solution
Total number of ways to choose 3 squares is 64C3. Starting from the 1st square at upperleft corner of 1st row, there is only one way to choose the remaining two squares from the second row adjacent to it such that they form the letter L and this is possible for all the 7 squares(excluding the 8th one) present in 1st row. Thus, it is 7 squares for one row. Similarly, for every 7 rows present(excluding the 8th one), it sums up to 7*7=49. The probability is 49/64C3. But this is not correct!