Selection rules electrostatic field

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Hi all , I need some help with this problem,

Homework Statement



A hydrogen atom, which is in its ground state |1 0 0 > , is put into a weak time-dependent external electric field, which points into the z direction:
[tex]\boldsymbol{E}(t,\boldsymbol{r}) = \frac{C\hat{\text{e}}_{z}}{t^{2}+\tau ^{2}}[/tex], where C and [tex]\tau > 0[/tex] and e are constants. This gives rise to a perturbation potential [tex]V(t) = C\frac{e\hat{z}}{t^{2}+\tau^{2}}[/tex].
Using lowest-order time-dependent perturbation theory, find the selection rules for transitions from the ground state, i.e. find out which final state values for the quantum numbers n, l and m are possible in transitions from the ground state.


Homework Equations



[tex]P_{fi}(t,t_{0})\equiv |\langle\phi_{f}|\psi(t)\rangle|^{2}\approx \frac{1}{\hbar^{2}}\left|\int_{t_{0}}^{t}\text{d}t _{1}\langle\phi_{f}|V_{S}(t_{1})|\phi_{i}\rangle \text{e}^{\text{i}(E_{f}-E_{i})t_{1}/\hbar}\right|^{2}.[/tex]

The Attempt at a Solution



First, I have to see the values of m for which the sandwich vanish i.e. [tex]< n l m| \hat{z} | 1 0 0 > =0[/tex]

[tex]< n l m| \hat{z} | 1 0 0 > = I (radial ) χ \int Y^*_{l,m} Cos [\theta]d \Omega Y_{0,0}[/tex]

The radial part is always non zero,

Therefore , i have to compute
[tex]\int d \Omega Y^*_{l,m} \cos (\theta) Y_{0,0} =[/tex] But I don't know what I can use, to compute the terms \cos (\theta) X spherical harmonics
thanks for your help!
 
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