Self Bias Transistor Design Problem

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The discussion revolves around solving for resistor values RD, RS1, and RS2 in a self-bias transistor design problem. RD has been calculated to be 2000 ohms using the AVNL equation with a given value of -8. However, the voltage gain approximation is incorrect without accounting for un-bypassed source resistance (RS1). To find RS1 and RS2, one should first determine the total source resistance using Vgs (quiescent) and then use Vds (quiescent) to refine the value of RD. A correct expression for voltage gain is necessary to accurately solve for RS1.
charkins
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Homework Statement


I have to solve for RD, RS1, and RS2.
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Homework Equations



AVNL=-mg(Rd//rd)
Vdd-Id(Rd+RStotal)=0
Bias Line Eq: Vg-Vgsq-Idq(RStotal)

The Attempt at a Solution


I have solved for RD by using the AVNL equation and the given value of -8 for AVNL.
I found RD to be 2000 ohms.

I cannot figure out how to get Rs1 and Rs2.
 
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charkins said:

The Attempt at a Solution


I have solved for RD by using the AVNL equation and the given value of -8 for AVNL.
I found RD to be 2000 ohms.

That's not correct. The voltage gain can only be approximated as (-gm Rd) if there is no un-bypassed source resistance (RS1).

Start by using the knowledge of Vgs (quiescent) to find the total source resistance (RS1+RS2), and then use the knowledge of Vds (quiescent) to find the value of RD.

Finally you need to derive (or look up) a correct expression for the voltage gain to solve for RS1.
 

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