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sovle the separable differential equation

4x-2y(x^2+1)^(1/2)(dy/dx)=0

using the following intial condition: y(0) = -3

y^2 = ? (function of x)

I guess that means the constant is -3

so i put all the x on 1 side and all the y on one side

4x = 2y(x^2+1)^(1/2)(dy/dx)

(4x)(dx) = 2y(x^2+1)^(1/2)(dy)

(4xdx)/(x^2+1)^(1/2) = 2ydy

integral both sides I got

4(x^2+1)^(1/2) = y^2

i tried the following answers

y^2 = 4(x^2+1)^(1/2)

y^2 = 4(x^2+1)^(1/2)+9

y^2 = 4(x^2+1)^(1/2)-3

they are all wrong!!!

WHAT IS WRONG?! IS MY WAY OF DOING IT TATALLY WRONG?!