Separable differential equation

  • Thread starter beanryu
  • Start date
  • #1
92
0
okay... i got this problem
sovle the separable differential equation
4x-2y(x^2+1)^(1/2)(dy/dx)=0
using the following intial condition: y(0) = -3
y^2 = ? (function of x)

I guess that means the constant is -3

so i put all the x on 1 side and all the y on one side

4x = 2y(x^2+1)^(1/2)(dy/dx)
(4x)(dx) = 2y(x^2+1)^(1/2)(dy)
(4xdx)/(x^2+1)^(1/2) = 2ydy

integral both sides I got
4(x^2+1)^(1/2) = y^2

i tried the following answers
y^2 = 4(x^2+1)^(1/2)
y^2 = 4(x^2+1)^(1/2)+9
y^2 = 4(x^2+1)^(1/2)-3

they are all wrong!!!

WHAT IS WRONG?! IS MY WAY OF DOING IT TATALLY WRONG?!
 

Answers and Replies

  • #2
789
4
This is correct. [tex]y^2=4\sqrt{x^2+1}+C[/tex]

Now plug in your initial condition to solve for C.
 
  • #3
208
0
well you got most of it but i dont know why you are trying 9 and -3 as c.

it says y(0) = -3

y = +-4*(x^2+1) + c

so y(0) = +-(0^2+1) + c = -3

can you figure it out from here
 
  • #4
92
0
if
y^2 = 4(x^2+1)^(1/2)+c
y = sqrt(4(x^2+1)^(1/2)+c)
c = 5 is the correct answer.

THANX!!!
 

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