The volume V of water in a particular container is related to the depth h of the water by the equation dV/dh below. If V = 0 when h = 0, find V when h = 4.
dV/dh = 16 sqrt(4-(h-2)2)
V(0) = 0
V(4) = ?
The Attempt at a Solution
I have not gotten the ODE in a form that I can integrate using separation of variables. I have gotten to the point dV/dh = 16 sqrt(-h2+4h) but this doesn't help much.