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## Homework Statement

[tex]\frac{dy}{dx} = e^{3x-3y} [/tex]

## Homework Equations

[tex]\int e^{u}du = e^u + C[/tex]

## The Attempt at a Solution

[tex]\frac{dy}{dx} = \frac{e^{3x}}{e^{3y}}[/tex]

[tex]e^{3y} dy = e^{3x} dx[/tex]

[tex] ln (e^{3y}) dy = ln (e^{3x}) dx[/tex]

[tex] 3y dy = 3x dx[/tex]

Integrate...

As you can see I'm doomed to get x = y

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