SammyS
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I get that T = 3.921875 pills ≈ 3.922 pills , so you're probably close enough for that answer.mundane said:For the 3% remaining problem I did this:
T=3.921 pills remaining, so
.03=3.921(1/2t/1 day=3.921t
log(1/2)(t)=log(.03/3.921)=log(.007)
log(1/2)(t)=-2.1163
-.301t=-2.1163
t=7.031 days (round up?)
Is this moderately close? At least tell me that ;'(
After, the 8th dose, the patient takes no more pills. The half-life of the pills is approximately 24 hours.
.03=3.921((1/2)t) is correct for t measured in days, but 3.921(1/2)t ≠ 3.921t . (Probably a typo, b/c the result is very good.)
Yes, I concur with your answer..