Series Convergence: What Can the Nth Term Test Tell Us?

woopydalan
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Homework Statement
Determine whether each of the following series converges or not.
## \sum_{n=1}^{\infty} \frac {n+3}{\sqrt{5n^2+1}}##
Relevant Equations
Divergence test, ratio test, etc
I'm not sure which test is the best to use, so I just start with a divergence test

##\lim_{n \to \infty} \frac {n+3}{\sqrt{5n^2+1}}##
The +3 and +1 are negligible
##\lim_{n \to \infty} \frac {n}{\sqrt{5n^2}}##

So now I have ##\infty / \infty##. So it's not conclusive. Trying ratio test

##\lim_{n \to \infty} \lvert \frac {n+4}{\sqrt{5(n+1)^2+1}} \cdot \frac {\sqrt{5n^2+1}}{n+3} \rvert##
seems to yield 1, so inconclusive

Integral test
## \int_{1}^{\infty} \frac {x+3}{\sqrt{5x^2+1}} dx ##. I could separate
## \int_{1}^{\infty} \frac {x}{\sqrt{5x^2+1}} dx + \int_{1}^{\infty} \frac {3}{\sqrt{5x^2+1}} dx ##
First part of the sum would be u-sub, not sure if I even know how to do the second part of the sum
 
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Think again about ##\displaystyle{\lim_{n \to \infty}\dfrac{n}{\sqrt{5n^2}}}.##
 
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I see, 1/sqrt(5)
 
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woopydalan said:
I see, 1/sqrt(5)
Ok, so what does the nth Term Test for Divergence tell you then?
 
woopydalan said:
So now I have ∞/∞.
Which means you haven't gone far enough in evaluating the limit. If you get any of the indeterminate forms, such as ##\frac \infty \infty, \frac 0 0, \infty - \infty,## or a few others, there is still work to do.
 
Mark44 said:
Ok, so what does the nth Term Test for Divergence tell you then?
Diverges if it's not 0
 
woopydalan said:
Diverges if it's not 0
What I meant was, what does the Nth Term Test tell you about this series, something I think you have now figured out.
 

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