- #1
ramsey2879
- 841
- 3
Given [tex]a_{0} = 0[/tex], [tex]a_{1} = 1[/tex], and [tex]a_n = Ba_{n-1} - a_{n-2}[/tex]; prove that
[tex]\sum_{i=1}^{m} a_{2i-1} = (a_{m})^2[/tex]
[tex]\sum_{i=1}^{m} a_{2i-1} = (a_{m})^2[/tex]