Series Resistor Problem: Finding the Equivalent Resistance

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Homework Help Overview

The discussion revolves around a problem involving the calculation of equivalent resistance in a circuit with resistors, specifically focusing on the configuration of resistors in series and parallel.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the relationships between resistors in series and parallel, with one original poster attempting to calculate equivalent resistance but expressing confusion about how to incorporate multiple resistors. Others clarify the configuration and suggest corrections to the calculations.

Discussion Status

Some participants have provided clarifications regarding the arrangement of resistors and have offered corrections to initial calculations. There appears to be an ongoing exploration of the correct approach to determining the equivalent resistance.

Contextual Notes

There is mention of confusion regarding the arrangement of resistors and the calculations involved, indicating potential misunderstandings about series and parallel configurations.

Mdhiggenz
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Homework Statement



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Homework Equations





The Attempt at a Solution



What I did was I knew that the their are two resistors in series

1/req= 1/R + 1/R = 1/2R

req= 2R

Where I get confused is how do I include the other resistor since I believe that it is in series?
 
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The two resistors on the left are in parallel , that is the current splits up through the two branches before going through the last one.
 
Wow my addition was off... I figured it out, it is supposed to be 2/R and since like you said it splits up the total resistance would be req=R/2

R/2 +R = 3R/2
 
Got it.
 

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